找回密码
 To register

QQ登录

只需一步,快速开始

扫一扫,访问微社区

Titlebook: Studies in Memory of Issai Schur; Anthony Joseph,Anna Melnikov,Rudolf Rentschler Book 2003 Springer Science+Business Media New York 2003 C

[复制链接]
楼主: digestive-tract
发表于 2025-3-26 23:22:16 | 显示全部楼层
https://doi.org/10.1007/978-1-4612-0045-1Cohomology; Dirac; Representation theory; algebra; homology; math physics
发表于 2025-3-27 02:57:57 | 显示全部楼层
发表于 2025-3-27 07:56:55 | 显示全部楼层
Studies in Memory of Issai Schur978-1-4612-0045-1Series ISSN 0743-1643 Series E-ISSN 2296-505X
发表于 2025-3-27 10:38:27 | 显示全部楼层
Dirac Cohomology for the Cubic Dirac Operator,and Z(g) be, respectively, the centers of the enveloping algebras of.and.. Using a Harish-Chandra isomorphism one has a homomorphism.which, by a well-known result of H. Cartan, yields the the relative Lie algebra cohomology .(..
发表于 2025-3-27 14:02:19 | 显示全部楼层
发表于 2025-3-27 20:40:57 | 显示全部楼层
发表于 2025-3-27 23:35:14 | 显示全部楼层
发表于 2025-3-28 04:44:30 | 显示全部楼层
Induced Representations of Affine Hecke Algebras and Canonical Bases of Quantum Groups,A criterion of irreducibility for induction products of evaluation modules of type A affine Hecke algebras is given. It is derived from multiplicative properties of the canonical basis of a quantum deformation of the Bernstein—Zelevinsky ring.
发表于 2025-3-28 07:00:46 | 显示全部楼层
Constructible Functions on Varieties Attached to Quivers,Let . be the enveloping algebra of a simple Lie algebra and let ., . be two simple finite-dimensional U-modules. (The ground field is the complex numbers.) We give a geometric realization of the tensor product of . and . in terms of constructible functions and we define a semicanonical basis of this tensor product.
发表于 2025-3-28 11:36:20 | 显示全部楼层
 关于派博传思  派博传思旗下网站  友情链接
派博传思介绍 公司地理位置 论文服务流程 影响因子官网 SITEMAP 大讲堂 北京大学 Oxford Uni. Harvard Uni.
发展历史沿革 期刊点评 投稿经验总结 SCIENCEGARD IMPACTFACTOR 派博系数 清华大学 Yale Uni. Stanford Uni.
|Archiver|手机版|小黑屋| 派博传思国际 ( 京公网安备110108008328) GMT+8, 2025-6-24 07:41
Copyright © 2001-2015 派博传思   京公网安备110108008328 版权所有 All rights reserved
快速回复 返回顶部 返回列表