Titlebook: Cardinal Functions on Boolean Algebras; J. Donald Monk Book 1990 Springer Basel AG 1990 algebra.Boolean algebra.cardinal function.function

bradycardia

书目名称Cardinal Functions on Boolean Algebras影响因子(影响力)




书目名称Cardinal Functions on Boolean Algebras影响因子(影响力)学科排名




书目名称Cardinal Functions on Boolean Algebras网络公开度




书目名称Cardinal Functions on Boolean Algebras网络公开度学科排名




书目名称Cardinal Functions on Boolean Algebras被引频次




书目名称Cardinal Functions on Boolean Algebras被引频次学科排名




书目名称Cardinal Functions on Boolean Algebras年度引用




书目名称Cardinal Functions on Boolean Algebras年度引用学科排名




书目名称Cardinal Functions on Boolean Algebras读者反馈




书目名称Cardinal Functions on Boolean Algebras读者反馈学科排名

Munificent

Stricture

Cardinality,.. = 2. for A satisfying CSP. W. Just [88] has shown that it is consistent to have a BA . such that ω. ≤ Card.. = |.| < 2ω. Questions about Card. are connected to some problems about cofinality and related cardinal functions which will not be considered here; see van Douwen [89]. The cardinal function Card. is defined as follows:

thalamus

Character,. ∈ . and ... = 0 for . ∉ .. Then . is the set of all.such that .. ≤ . for some cofinite subset . of .. So, it is clear that . ≤ .|. If . is a set of generators for . with |.| < |.|, then there is a . ∈ . such that . ⊆ .. for infinitely many cofinite subsets . of .; this is clearly impossible.

neutralize

爱国者

爱国者

https://doi.org/10.1007/978-981-99-7879-3of . such that . ⊆ .. But it is a very elementary exercise to show that no ultrafilter is included in a finite union of other, different, ultrafilters. So, t. ≥ ., and hence t. ≥ . for every infinite BA ..

LAP

,-Weight, . with π . < π ., and if we take . = . and . = ./Fin, then π . = ω; while π . = 2. since A has a disjoint subset of size 2.. Turning to products, we have (math) for any system (.. : . ∈ .) of infinite BA’s. For, ≥ is clear; now suppose .. is a dense subset of .. for each . ∈ ..

anchor

graphy

Tightness,of . such that . ⊆ .. But it is a very elementary exercise to show that no ultrafilter is included in a finite union of other, different, ultrafilters. So, t. ≥ ., and hence t. ≥ . for every infinite BA ..