神像之光环 发表于 2025-3-21 16:55:19
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we need a far more precise description of the first order degenerations (13 in all) than that given by Schubert and this is obtained by proving a number of key geometric relations that are satisfied by cuspidal cubics. Moreover, our procedure does not require using coincidence formulas to derive the basic degeneration relations.calorie 发表于 2025-3-22 00:29:21
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Alan Walker,John Humphreys we need a far more precise description of the first order degenerations (13 in all) than that given by Schubert and this is obtained by proving a number of key geometric relations that are satisfied by cuspidal cubics. Moreover, our procedure does not require using coincidence formulas to derive the basic degeneration relations.d-limonene 发表于 2025-3-22 20:03:29
Ray Land,John Humphreys we need a far more precise description of the first order degenerations (13 in all) than that given by Schubert and this is obtained by proving a number of key geometric relations that are satisfied by cuspidal cubics. Moreover, our procedure does not require using coincidence formulas to derive the basic degeneration relations.是剥皮 发表于 2025-3-23 00:53:42
Bill Bailey,John Humphreys we need a far more precise description of the first order degenerations (13 in all) than that given by Schubert and this is obtained by proving a number of key geometric relations that are satisfied by cuspidal cubics. Moreover, our procedure does not require using coincidence formulas to derive the basic degeneration relations.发源 发表于 2025-3-23 02:54:00
Stephanie Stanwick we need a far more precise description of the first order degenerations (13 in all) than that given by Schubert and this is obtained by proving a number of key geometric relations that are satisfied by cuspidal cubics. Moreover, our procedure does not require using coincidence formulas to derive the basic degeneration relations.laparoscopy 发表于 2025-3-23 07:03:40
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