CODA
发表于 2025-3-23 11:54:36
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Grating
发表于 2025-3-23 16:54:31
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全能
发表于 2025-3-23 19:12:22
Prime levels ,=,≥5Koninkl. Nederl. Akad. Wetensch. 55:498–503, .) and Schoeneberg (Koninkl. Nederl. Akad. Wetensch. 70:177–182, .). For .=5 and .=7 theta series identities involving real quadratic fields are known from (Kac and Peterson in Adv. Math. 53:125–264, .), (Hiramatsu in Investigations in Number Theory. Advanced Studies in Pure Math. 13:503–584, .).
unstable-angina
发表于 2025-3-24 01:39:56
An Algorithm for Listing Lattice Points in a Simplexic eta products of a given level . and weight .. The results in Sect. 3 say that we get this list when we list up all the lattice points in a certain compact simplex. Every single lattice point represents an interesting function, and we really need such a list.
FLAX
发表于 2025-3-24 04:28:09
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Pastry
发表于 2025-3-24 07:45:23
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温顺
发表于 2025-3-24 14:04:09
https://doi.org/10.1007/978-3-030-48822-2ince Jacobi’s .(.) is a modular form for .(2). Several of the results in Sects. 10, 11 and 13 are transcriptions of earlier research (Köhler in Abh. Math. Sem. Univ. Hamburg 55, 75–89, .), (Köhler in Math. Z. 197, 69–96, .), (Köhler in Abh. Math. Sem. Univ. Hamburg 58, 15–45, .) on theta series on these three Hecke groups.
Magisterial
发表于 2025-3-24 18:14:39
Spoken Transgression and the Courts,oduct of level . and weight 1 for primes .≥5. The eta product .(.).(3.) is identified with a Hecke theta series for .; the result (11.2) is known from (Dummit et al. in Finite Groups—Coming of Age. Contemp. Math. 45, 89–98, .), (Köhler in Math. Z. 197, 69–96, .).
GOUGE
发表于 2025-3-24 19:31:05
Dedekind’s Eta Function and Modular Forms disc or, equivalently, for . in the . ℍ={.∈ℂ∣Im(.)>0}. This means that the product of the absolute values |1−..| converges uniformly for . in every compact subset of ℍ. The normal convergence of the product implies that . is a holomorphic function on ℍ and that .(.)≠0 for all .∈ℍ.
ALLEY
发表于 2025-3-25 02:45:10
Eta Productss from ℤ, positive or negative or 0. (Of course, an exponent 0 contributes a trivial factor 1 to the product, and therefore we may as well assume that ..≠0 for all ..) Since the product is finite, the lowest common multiple .=lcm {.} exists, and every . divides ..