surrogate 发表于 2025-3-28 15:40:47
Elements of Nonlinear Analysis, .(.) denote the Banach space of bounded linear operators from . to Y with the operator topology. We also assume the reader is familiar with integration of functions with values in a Banach space. For . in a Banach space, the symbol 0(|.|) as |.| → 0 denotes a function such that 0(|.|)/|.| is bounde乳白光 发表于 2025-3-28 21:53:36
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Bifurcation with One Dimensional Null Space,scalar or an .-dimensional vector, but the criterion for bifurcation was based only upon the linear approximation to .(.) near . = 0, namely, the operator ..(., 0). If . and . is an eigenvalue of (.,..., .) possessing certain properties, then it was shown that. . is always a bifurcation point for .(Crayon 发表于 2025-3-29 08:07:31
Bifurcation with Higher Dimensional Null Spaces,f Liapunov–Schmidt reduces the study of local bifurcation to the study of a system of nonlinear equations .(.) = 0 for . ∈ ℝ., . ∈ ℝ., where . = dim N(.(0,0)). If . 1 and ..(0,0)/. ≠ 0, we have seen in Section 6.2 that the local bifurcations are determined by a scalar function of .. If .(0,0)/. = 0,江湖郎中 发表于 2025-3-29 11:46:01
Some Applications, to the buckling of thin rectangular plates and cylindrical shells with small curvature. The bifurcation parameters are chosen to be external loading, imperfections, curvature and the ratio of the sides of the plate. The ratio of the sides is allowed to be in a neighborhood of a value for which theInterstellar 发表于 2025-3-29 17:51:25
Bifurcation near Equilibrium, we consider an equation.in a Banach space . for . in a Banach space .(0, 0) = 0, .(0, 0)/. 0 under the assumption that the linear operator . has zero as a simple eigen-value. The method of Liapunov—Schmidt gives a scalar bifurcation function .(.) defined for .) in neighborhood of (0, 0) ∈ ℝ × .. SuDEFT 发表于 2025-3-29 23:03:10
http://reply.papertrans.cn/64/6324/632358/632358_48.pngcommitted 发表于 2025-3-30 00:01:27
Higher Order Bifurcation near Equilibrium,oint of degree one. In particular, for any equilibrium point, this implies that the linear variational equation must either have only zero as a simple eigenvalue and no other eigenvalue on the imaginary axis or have only a pair of simple complex eigenvalues on the imaginary axis. Generically, the fiMANIA 发表于 2025-3-30 07:32:16
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