chiropractor 发表于 2025-3-25 07:29:43

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vibrant 发表于 2025-3-25 12:24:14

The Join of the Pseudovariety J with Permutative Pseudovarieties,rization of the implict operations on ., we calculate some joins of the form .∨ ., where . is a permutative pseudovariety. As a consequence we obtain that, for these ., . ∨ . is decidable if and only if . ∩ . is decidable.

Fibrillation 发表于 2025-3-25 16:33:31

Some Examples of Distributive Ockham Algebras with de Morgan Skeletons,; . ∈ .} is a subalgebra which we call the . of .; it is a de Morgan algebra precisely when .. = .. A study of the class .. of Ockham algebras in which .. = .. for p ≥ 1, q ≥ 0 was initiated by Berman in . The Ockham algebras with de Morgan skeletons thus constitute the class ...

diabetes 发表于 2025-3-25 23:36:25

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Assemble 发表于 2025-3-26 04:11:32

Inverse Semigroups of Bicongruences on Algebras, Particularly Semilattices,rmation is explored in the case of semilattices; the main result is that any (meet) semilattice admitting no joins of incomparable elements, and satisfying chain conditions, is determined up to isomorphism by the inverse semigroup of isomorphisms between its quotient semilattices.

色情 发表于 2025-3-26 06:17:08

Finitely Presented Lattices: Continuity and Semidistributivity,anonical form for the elements of such a lattice and used this to study the covering relation. We showed that there is an effective procedure for finding the covers of any element of a finitely presented lattice. We gave an example of a finitely presented lattice which has no cover at all.

事情 发表于 2025-3-26 08:31:51

The Complete Congruence Lattice of a Complete Lattice,nitary) algebra? In 1948, Birkhoff restated this question in the Second Edition of his Lattice Theory ; however, “(infinitary)” was dropped from the question. This was intentional; G. Birkhoff referred to some continuity conditions that must hold in a congruence lattice of a (finitary) algebra.

琐碎 发表于 2025-3-26 14:07:00

Semigroup Graded Rings and Jacobson Rings,n abelian group of finite torsion free rank are Jacobson rings in case the identity component is a left Noetherian Jacobson ring. For monoid rings R of abelian monoids of finite rank the same result holds without R being left Noetherian.

Anthropoid 发表于 2025-3-26 18:58:05

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Exonerate 发表于 2025-3-26 22:26:52

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查看完整版本: Titlebook: Lattices, Semigroups, and Universal Algebra; Jorge Almeida,Gabriela Bordalo,Philip Dwinger Book 1990 Springer Science+Business Media New Y