粗糙
发表于 2025-3-23 10:47:06
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可触知
发表于 2025-3-23 14:23:37
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有限
发表于 2025-3-23 19:31:47
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Tortuous
发表于 2025-3-23 23:40:01
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Abnormal
发表于 2025-3-24 03:44:16
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ABIDE
发表于 2025-3-24 08:58:27
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endure
发表于 2025-3-24 13:34:15
Invariant Subspaces,. into itself, so that .[.] is the formed algebra of all operators on .. If . ≠ {0}, then .[.] contains the identity operator . and ||.|| = 1, which means that .[.] is a . formed algebra. Recall that .[., .] is a Banach space whenever . is a Banach space so that .[.] is a unital Banach algebra whene
tooth-decay
发表于 2025-3-24 16:32:21
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掺和
发表于 2025-3-24 22:17:54
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断言
发表于 2025-3-25 01:20:03
Reducing Subspaces,n Theorem) says that, if . is a Hilbert space and . is a subspace of ., then . + . = .. In other words, . (see e.g., ). Thus, in a Hilbert space, every subspace has a complementary subspace, and this only happens in a Hilbert space .