思考才皱眉 发表于 2025-3-26 20:56:28
http://reply.papertrans.cn/43/4247/424632/424632_31.png征服 发表于 2025-3-27 04:46:45
http://reply.papertrans.cn/43/4247/424632/424632_32.png物质 发表于 2025-3-27 05:59:05
http://reply.papertrans.cn/43/4247/424632/424632_33.pngHEW 发表于 2025-3-27 13:16:52
Philip Burnard we need a far more precise description of the first order degenerations (13 in all) than that given by Schubert and this is obtained by proving a number of key geometric relations that are satisfied by cuspidal cubics. Moreover, our procedure does not require using coincidence formulas to derive the basic degeneration relations.极少 发表于 2025-3-27 13:51:38
Philip Burnard we need a far more precise description of the first order degenerations (13 in all) than that given by Schubert and this is obtained by proving a number of key geometric relations that are satisfied by cuspidal cubics. Moreover, our procedure does not require using coincidence formulas to derive the basic degeneration relations.antiandrogen 发表于 2025-3-27 20:00:02
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http://reply.papertrans.cn/43/4247/424632/424632_37.pngSTENT 发表于 2025-3-28 05:26:39
http://reply.papertrans.cn/43/4247/424632/424632_38.png指令 发表于 2025-3-28 10:15:43
Philip Burnard we need a far more precise description of the first order degenerations (13 in all) than that given by Schubert and this is obtained by proving a number of key geometric relations that are satisfied by cuspidal cubics. Moreover, our procedure does not require using coincidence formulas to derive the basic degeneration relations.hypnotic 发表于 2025-3-28 14:12:24
Philip Burnard we need a far more precise description of the first order degenerations (13 in all) than that given by Schubert and this is obtained by proving a number of key geometric relations that are satisfied by cuspidal cubics. Moreover, our procedure does not require using coincidence formulas to derive the basic degeneration relations.