CROAK 发表于 2025-3-25 05:08:05
978-3-540-09762-4Springer-Verlag Berlin Heidelberg 1980Type-1-Diabetes 发表于 2025-3-25 11:33:24
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0075-8434 Overview: 978-3-540-09762-4978-3-540-38645-2Series ISSN 0075-8434 Series E-ISSN 1617-9692TIGER 发表于 2025-3-25 17:38:12
https://doi.org/10.1007/978-981-10-6493-7.). Next, White picks a compact interval W. ⊂ B. of length ℓ(W.) = αℓ(B.). Then Black picks a compact interval B. ⊂ W. of length ℓ(B.) = βℓ(W.), etc. In this way, a nested sequence of compact intervals . is generated, with lengths . It is clear that . consists of a single point.NAIVE 发表于 2025-3-25 21:31:26
https://doi.org/10.1007/978-981-10-6493-7me of K. (By the volume of K we mean the Riemann integral of the characteristic function of K. It can be proved that every convex body has a volume in this sense. Alternatively, the existence of the volume of K may be added as a hypothesis.)忙碌 发表于 2025-3-26 03:15:16
Simultaneous Approximation to Algebraic Numbers,roximable, so that . where q.,...,q., p are rational integers and where q = max(|q.|,...,|q.|) ≠ 0. Taking q. = ... = q. = 0, we have .. . 1,..,...,... ℚ, . d. ... q.,...,q., p . q = max(|q.|,..., |q.|) > 0.鸽子 发表于 2025-3-26 06:06:41
Norm Form Equations,n element . of K under ϕ. by ϕ.. We will always tacitly assume that ϕ., is the identity map, so that .. = ., and we shall say that .. = ., ..,..... are the conjugates of .. In this notation ℜ(.) = ........ Given a linear form . with coefficients in K we write密码 发表于 2025-3-26 10:34:18
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Complex Landscapes of Spatial Interactionn element . of K under ϕ. by ϕ.. We will always tacitly assume that ϕ., is the identity map, so that .. = ., and we shall say that .. = ., ..,..... are the conjugates of .. In this notation ℜ(.) = ........ Given a linear form . with coefficients in K we write翅膀拍动 发表于 2025-3-26 20:22:54
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