脖子
发表于 2025-3-26 21:41:03
Walter Sebron,Hans Tschürtz,Peter Krebsknown algorithms when a system contains a few linearly independent monomials. For parametric binomial systems we construct an algorithm of polynomial complexity. We discuss the applications of these algorithms in the context of chemical reaction systems.
BLINK
发表于 2025-3-27 02:24:45
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MODE
发表于 2025-3-27 05:54:03
Alexander Poth,Simon Field,Marc Koeslingrating or at least separating subsets of rings of invariants. This talk gives some examples in which invariant theory is applied to graph theory, computer vision, and coding theory. We also give an overview of the state of the art of algorithmic invariant theory.
glacial
发表于 2025-3-27 09:28:13
Vladimir P. Gerdt,Wolfram Koepf,Evgenii V. VorozhtUp-to-date results.Fast-track conference proceedings.State-of-the-art research
椭圆
发表于 2025-3-27 16:08:58
Lecture Notes in Computer Sciencehttp://image.papertrans.cn/c/image/233420.jpg
BLAZE
发表于 2025-3-27 19:37:26
An Algebraic Characterization of Rainbow Connectivity, polynomial equations. We first consider the case of two colors for which the problem is known to be hard and we then extend the approach to the general case. We also present a formulation of the rainbow connectivity problem as an ideal membership problem.
micronized
发表于 2025-3-27 22:35:05
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Palpitation
发表于 2025-3-28 05:31:03
Quasi-stability versus Genericity, the generic initial ideal. In contrast to genericity, quasi-stability is a characteristic independent property that can be effectively verified. We also relate Pommaret bases to some invariants associated with local cohomology, exhibit the existence of linear quotients in Pommaret bases and prove some results on componentwise linear ideals.
lattice
发表于 2025-3-28 09:45:20
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debase
发表于 2025-3-28 13:27:01
Michel Picard,Alain Renault,Béatrix Barafortsolutions is algorithmically undecidable. However, for equations with constant coefficients this question can be decided very easily since such an equation has a non-zero polynomial solution iff its constant term is zero. We give a simple combinatorial proof of the fact that in this case the equatio