minuscule
发表于 2025-3-21 18:23:18
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衰老
发表于 2025-3-21 23:47:35
Latin squares composed of four disjoint subsquares,
Myosin
发表于 2025-3-22 02:22:33
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prosthesis
发表于 2025-3-22 06:50:31
The knotted hexagon,al position in E.) be the set of vertices of some knotted hexagon, it is necessary that the convex hull K of the six points have six vertices (i.e. that no point lie inside the convex hull of the other five) and it is necessary and sufficient that K be of a certain combinatorial type, there being tw
colloquial
发表于 2025-3-22 12:07:34
Sum-free sets in loops,he converse problem, of finding a sum-free partition and then obtaining the colouring looks like being much harder. Note also that there are still colourings of K. which cannot be obtained in this way. For example, if the colouring shown in Figure 7 were obtainabl from a loop {0,1,2,3,4,5} then thre
Between
发表于 2025-3-22 16:46:46
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Between
发表于 2025-3-22 17:32:48
,A schröder triangle: Three combinatorial problems,. Three combinatorial interpretations of the sequences are given which are variants of interpretations of the Catalan numbers. The method of enumeration used is that of first or last passage decomposition. This leads to a renewal array having many of the properties of Pascal‘s triangle.
projectile
发表于 2025-3-23 01:06:19
Anne Germain,Rebecca Campbell,Ashlee McKeone elements, say {1,2,3} would have to be in one of the sum-free sets. But then {0,4,5} would, by 3.1, be a subloop, and so neither 0–4 nor 4–0 could belong to {1,2,3}. (However, Heinrich has shown that this colouring can be embedded in a colouring of K. obtained from a sum-free partition of Z.).
CLIFF
发表于 2025-3-23 05:27:41
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RENIN
发表于 2025-3-23 06:26:43
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