acrophobia
发表于 2025-4-1 04:09:15
Guilherme Kosmann,Ronaldo de Luciopt of a “.”. A continuation is an actor which is prepared to accept an (intermediate) value as a message, and continue the computation. In SmallTalk-80. an object (or actor) will instead return a message to the object which instigated the computation, in much the same way that a Pascal function will return a value to the routine which called it.
calumniate
发表于 2025-4-1 06:07:54
Actors,pt of a “.”. A continuation is an actor which is prepared to accept an (intermediate) value as a message, and continue the computation. In SmallTalk-80. an object (or actor) will instead return a message to the object which instigated the computation, in much the same way that a Pascal function will return a value to the routine which called it.
美食家
发表于 2025-4-1 11:12:14
http://reply.papertrans.cn/23/2225/222425/222425_63.png
orient
发表于 2025-4-1 15:29:56
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构想
发表于 2025-4-1 21:59:58
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宣誓书
发表于 2025-4-2 01:37:31
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流动性
发表于 2025-4-2 03:42:02
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