食道
发表于 2025-3-27 00:38:55
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用肘
发表于 2025-3-27 01:25:38
Hereditary Density,We begin again with some equivalent definitions, which are similar to the case of hereditary Lindelöf degree. Recall from page 42 the definition of left-separated sequence.
放肆的我
发表于 2025-3-27 08:21:17
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Decrepit
发表于 2025-3-27 12:21:45
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Ganglion-Cyst
发表于 2025-3-27 14:52:00
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Glower
发表于 2025-3-27 19:24:37
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混杂人
发表于 2025-3-28 00:10:25
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高脚酒杯
发表于 2025-3-28 04:35:31
https://doi.org/10.1007/0-387-31609-4t its behaviour under ultraproducts are the same as the well-known and difficult problems concerning the cardinality of ultraproducts in general. Card. is a non-obvious function. Clearly Card.. ≤ 2. for every infinite BA, and Card.. = ω for many BAs, e.g. for free BAs and interval algebras. But Card
cushion
发表于 2025-3-28 09:52:30
https://doi.org/10.1007/978-981-99-7879-3h that 0 < y < .; hence there is an ultrafilter .. such that . ∈ .. but .. ≠ .. Let . = {.. : . ∈ .}. Thus . ⊆ ⋃ .. Suppose that . is a finite subset of . such that . ⊆ .. But it is a very elementary exercise to show that no ultrafilter is included in a finite union of other, different, ultrafilters
现晕光
发表于 2025-3-28 12:49:15
Feeding, Foraging, and Predation, an ultrafilter on .]. Clearly then, by topological duality, .(.) = sup(.A, .). For a weak product we have.. To show this, it suffices to show that . = |.| for the “new” ultrafilter .. This ultrafilter is defined as follows. For each subset . of ., let .. be the element of Π... such that ... = 1 if