SOBER
发表于 2025-3-26 22:01:35
Computing Rational Points on Rank 0 Genus 3 Hyperelliptic Curves, Chabauty–Coleman method to find the zero set of a certain system of .-adic integrals, which is known to be finite and include the set of rational points .. We implemented an algorithm in Sage to carry out the Chabauty–Coleman method on a database of 5870 curves.
guardianship
发表于 2025-3-27 03:12:04
Curves with Sharp Chabauty-Coleman Bound,al points if the rank condition is satisfied. We give numerous examples of genus two and rank one curves for which Coleman’s bound is sharp. Based on one of those curves, we construct an example of a curve of genus five whose rational points are determined using the descent method together with Cole
right-atrium
发表于 2025-3-27 05:26:09
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palliative-care
发表于 2025-3-27 11:57:29
Linear Dependence Among Hecke Eigenvalues,n cuspidal eigenform. Our motivation lies in its algorithmic application. For any fixed positive integer ., the bound established here yields an algorithm that computes cuspidal Hecke eigenforms with a given weight . whose Hecke eigenvalues generate a number field of degree .. The resulting algorith
FACT
发表于 2025-3-27 17:20:18
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设施
发表于 2025-3-27 20:52:19
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不出名
发表于 2025-3-28 00:02:40
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铺子
发表于 2025-3-28 06:02:07
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形上升才刺激
发表于 2025-3-28 10:06:37
Curves with Sharp Chabauty-Coleman Bound,al points if the rank condition is satisfied. We give numerous examples of genus two and rank one curves for which Coleman’s bound is sharp. Based on one of those curves, we construct an example of a curve of genus five whose rational points are determined using the descent method together with Coleman’s theorem.
宇宙你
发表于 2025-3-28 10:28:44
Linear Dependence Among Hecke Eigenvalues,n cuspidal eigenform. Our motivation lies in its algorithmic application. For any fixed positive integer ., the bound established here yields an algorithm that computes cuspidal Hecke eigenforms with a given weight . whose Hecke eigenvalues generate a number field of degree .. The resulting algorithm reduces to Cremona’s when . = 1 and . = 2.